Base | Representation |
---|---|
bin | 11100111101110000011… |
… | …01110110001111001011 |
3 | 10112010212011012221011211 |
4 | 32132320031312033023 |
5 | 112301211342130042 |
6 | 2041111303433551 |
7 | 131621452062004 |
oct | 16367015661713 |
9 | 3463764187154 |
10 | 995228083147 |
11 | 35408a342161 |
12 | 140a6ba558b7 |
13 | 72b077778bc |
14 | 362527981ab |
15 | 1ad4c865017 |
hex | e7b83763cb |
995228083147 has 4 divisors (see below), whose sum is σ = 996164328880. Its totient is φ = 994291837416.
The previous prime is 995228083093. The next prime is 995228083177. The reversal of 995228083147 is 741380822599.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 741380822599 = 471589 ⋅1572091.
It is a cyclic number.
It is not a de Polignac number, because 995228083147 - 231 = 993080599499 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 995228083091 and 995228083100.
It is not an unprimeable number, because it can be changed into a prime (995228083177) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 468121272 + ... + 468123397.
It is an arithmetic number, because the mean of its divisors is an integer number (249041082220).
Almost surely, 2995228083147 is an apocalyptic number.
995228083147 is a deficient number, since it is larger than the sum of its proper divisors (936245733).
995228083147 is a wasteful number, since it uses less digits than its factorization.
995228083147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 936245732.
The product of its (nonzero) digits is 8709120, while the sum is 58.
The spelling of 995228083147 in words is "nine hundred ninety-five billion, two hundred twenty-eight million, eighty-three thousand, one hundred forty-seven".
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