9955603 has 4 divisors (see below), whose sum is σ = 11377840. Its totient is φ = 8533368.

The previous prime is 9955577. The next prime is 9955633. The reversal of 9955603 is 3065599.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3065599 = 43 ⋅71293.

It is a cyclic number.

It is not a de Polignac number, because 9955603 - 2⁵ = 9955571 is a prime.

It is a super-2 number, since 2×9955603² = 198228062187218, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (9955633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 711108 + ... + 711121.

It is an arithmetic number, because the mean of its divisors is an integer number (2844460).

Almost surely, 2^9955603 is an apocalyptic number.

9955603 is a deficient number, since it is larger than the sum of its proper divisors (1422237).

9955603 is a wasteful number, since it uses less digits than its factorization.

9955603 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1422236.

The product of its (nonzero) digits is 36450, while the sum is 37.

The square root of 9955603 is about 3155.2500693289. The cubic root of 9955603 is about 215.1241612025.

The spelling of 9955603 in words is "nine million, nine hundred fifty-five thousand, six hundred three".