Base | Representation |
---|---|
bin | 1001000011100101001001… |
… | …0000000110100101101011 |
3 | 1022020220001101221002200020 |
4 | 2100321102100012211223 |
5 | 2301114132210121011 |
6 | 33102122440211523 |
7 | 2045243366525406 |
oct | 220712220064553 |
9 | 38226041832606 |
10 | 9957114145131 |
11 | 319987439855a |
12 | 1149909469ba3 |
13 | 572c4b24873a |
14 | 265cd958cd3d |
15 | 124019e13006 |
hex | 90e5240696b |
9957114145131 has 4 divisors (see below), whose sum is σ = 13276152193512. Its totient is φ = 6638076096752.
The previous prime is 9957114145117. The next prime is 9957114145151. The reversal of 9957114145131 is 1315414117599.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 9957114145131 - 29 = 9957114144619 is a prime.
It is a super-2 number, since 2×99571141451312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (9957114145151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1659519024186 + ... + 1659519024191.
It is an arithmetic number, because the mean of its divisors is an integer number (3319038048378).
Almost surely, 29957114145131 is an apocalyptic number.
9957114145131 is a deficient number, since it is larger than the sum of its proper divisors (3319038048381).
9957114145131 is a wasteful number, since it uses less digits than its factorization.
9957114145131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3319038048380.
The product of its digits is 680400, while the sum is 51.
The spelling of 9957114145131 in words is "nine trillion, nine hundred fifty-seven billion, one hundred fourteen million, one hundred forty-five thousand, one hundred thirty-one".
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