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9970305035 = 51994061007
BaseRepresentation
bin10010100100100011…
…01100100000001011
3221201211212222021212
421102101230200023
5130404344230120
64325202123335
7502034123465
oct112221544013
927654788255
109970305035
114256a82819
121b2305054b
13c2b7c12a2
146a8233135
153d54946c5
hex25246c80b

9970305035 has 4 divisors (see below), whose sum is σ = 11964366048. Its totient is φ = 7976244024.

The previous prime is 9970305019. The next prime is 9970305049. The reversal of 9970305035 is 5305030799.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 9970305035 - 24 = 9970305019 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 9970304983 and 9970305001.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 997030499 + ... + 997030508.

It is an arithmetic number, because the mean of its divisors is an integer number (2991091512).

Almost surely, 29970305035 is an apocalyptic number.

9970305035 is a deficient number, since it is larger than the sum of its proper divisors (1994061013).

9970305035 is a wasteful number, since it uses less digits than its factorization.

9970305035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1994061012.

The product of its (nonzero) digits is 127575, while the sum is 41.

The square root of 9970305035 is about 99851.4147871726. The cubic root of 9970305035 is about 2152.3000469399.

The spelling of 9970305035 in words is "nine billion, nine hundred seventy million, three hundred five thousand, thirty-five".

Divisors: 1 5 1994061007 9970305035