9992001403 has 8 divisors (see below), whose sum is σ = 10007205120. Its totient is φ = 9976811880.

The previous prime is 9992001307. The next prime is 9992001433. The reversal of 9992001403 is 3041002999.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 9992001403 - 2⁹ = 9992000891 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (9992001433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2650626 + ... + 2654392.

It is an arithmetic number, because the mean of its divisors is an integer number (1250900640).

Almost surely, 2^9992001403 is an apocalyptic number.

9992001403 is a deficient number, since it is larger than the sum of its proper divisors (15203717).

9992001403 is a wasteful number, since it uses less digits than its factorization.

9992001403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7097.

The product of its (nonzero) digits is 17496, while the sum is 37.

The square root of 9992001403 is about 99959.9990146058. Note that the first 3 decimals coincide. The cubic root of 9992001403 is about 2153.8601216517.

The spelling of 9992001403 in words is "nine billion, nine hundred ninety-two million, one thousand, four hundred three".