Numbers which belong to a Fibonacci-like sequence in which each term is the sum of the reverse of the two previous terms. more
The iccanobiF numbers up to 1.1×10
14 :
1,
2,
3,
5,
8,
13,
39,
124,
514,
836,
1053,
4139,
12815,
61135,
104937,
792517,
1454698,
9679838,
17354310,
9735140,
1760750,
986050,
621360,
113815,
581437,
1252496,
7676706,
13019288,
94367798,
178067380,
173537220,
106496242,
265429972,
522619163,
641840787,
1148964371,
2521746557,
9291169663,
11226083181,
21807674140,
22285733023,
36181429034,
75126176385,
101459580320,
81453116258,
108347089519,
1001241879219,
10045762164802,
29975908175002,
40903307711993,
59968951288896,
109799986317899.
Distribution of the remainders when the numbers in this family are divided by n=2, 3,..., 11. (I took into account 52 values, from 1 to 109799986317899).
n\r | 0 | 1 |
2 | 27 | 25 | 2 |
3 | 13 | 19 | 20 | 3 |
4 | 13 | 11 | 14 | 14 | 4 |
5 | 14 | 7 | 10 | 13 | 8 | 5 |
6 | 5 | 9 | 12 | 8 | 10 | 8 | 6 |
7 | 9 | 8 | 9 | 10 | 3 | 7 | 6 | 7 |
8 | 6 | 4 | 10 | 7 | 7 | 7 | 4 | 7 | 8 |
9 | 4 | 11 | 5 | 5 | 4 | 5 | 4 | 4 | 10 | 9 |
10 | 9 | 3 | 5 | 7 | 3 | 5 | 4 | 5 | 6 | 5 | 10 |
11 | 5 | 4 | 3 | 8 | 2 | 5 | 4 | 3 | 8 | 4 | 6 |
A pictorial representation of the table above
Imagine to divide the members of this family by a number n and compute the remainders. Should they be uniformly distributed, each remainder from 0 to n-1 would be obtained in about (1/n)-th of the cases. This outcome is represented by a white square. Reddish (resp. bluish) squares represent remainders which appear more (resp. less) frequently than 1/n.