Base | Representation |
---|---|
bin | 1001000110000110100001… |
… | …0000111011001110001111 |
3 | 1022102000212101020122211021 |
4 | 2101201220100323032033 |
5 | 2302321341340214211 |
6 | 33134045140335011 |
7 | 2051336025042130 |
oct | 221415020731617 |
9 | 38360771218737 |
10 | 10000433132431 |
11 | 3206183879905 |
12 | 11561989a4467 |
13 | 577062aca7c1 |
14 | 268048879c87 |
15 | 125202e9d771 |
hex | 9186843b38f |
10000433132431 has 16 divisors (see below), whose sum is σ = 11443059226368. Its totient is φ = 8561308392000.
The previous prime is 10000433132419. The next prime is 10000433132441. The reversal of 10000433132431 is 13423133400001.
It is not a de Polignac number, because 10000433132431 - 211 = 10000433130383 is a prime.
It is a super-2 number, since 2×100004331324312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10000433132396 and 10000433132405.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10000433132411) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38903916 + ... + 39160126.
It is an arithmetic number, because the mean of its divisors is an integer number (715191201648).
Almost surely, 210000433132431 is an apocalyptic number.
10000433132431 is a deficient number, since it is larger than the sum of its proper divisors (1442626093937).
10000433132431 is an equidigital number, since it uses as much as digits as its factorization.
10000433132431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 263022.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 10000433132431 its reverse (13423133400001), we get a palindrome (23423566532432).
The spelling of 10000433132431 in words is "ten trillion, four hundred thirty-three million, one hundred thirty-two thousand, four hundred thirty-one".
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