Base | Representation |
---|---|
bin | 10110101111010101100101… |
… | …001110110110011011100011 |
3 | 111010002212022200102200112012 |
4 | 112233111211032312123203 |
5 | 101102031001020113024 |
6 | 552411544252023135 |
7 | 30031325216541245 |
oct | 2657254516663343 |
9 | 433085280380465 |
10 | 100010011879139 |
11 | 2995900a4a515a |
12 | b27273a761aab |
13 | 43a5b9943239b |
14 | 1a9a720788095 |
15 | b8675372750e |
hex | 5af5653b66e3 |
100010011879139 has 2 divisors, whose sum is σ = 100010011879140. Its totient is φ = 100010011879138.
The previous prime is 100010011879111. The next prime is 100010011879159. The reversal of 100010011879139 is 931978110010001.
It is a strong prime.
It is an emirp because it is prime and its reverse (931978110010001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100010011879139 - 216 = 100010011813603 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100010011879096 and 100010011879105.
It is not a weakly prime, because it can be changed into another prime (100010011879109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005005939569 + 50005005939570.
It is an arithmetic number, because the mean of its divisors is an integer number (50005005939570).
Almost surely, 2100010011879139 is an apocalyptic number.
100010011879139 is a deficient number, since it is larger than the sum of its proper divisors (1).
100010011879139 is an equidigital number, since it uses as much as digits as its factorization.
100010011879139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608, while the sum is 41.
The spelling of 100010011879139 in words is "one hundred trillion, ten billion, eleven million, eight hundred seventy-nine thousand, one hundred thirty-nine".
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