100010311113331 has 2 divisors, whose sum is σ = 100010311113332. Its totient is φ = 100010311113330.

The previous prime is 100010311113299. The next prime is 100010311113337. The reversal of 100010311113331 is 133311113010001.

It is a strong prime.

It is an emirp because it is prime and its reverse (133311113010001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100010311113331 - 2⁵ = 100010311113299 is a prime.

It is a super-2 number, since 2×100010311113331² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100010311113299 and 100010311113308.

It is not a weakly prime, because it can be changed into another prime (100010311113337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005155556665 + 50005155556666.

It is an arithmetic number, because the mean of its divisors is an integer number (50005155556666).

Almost surely, 2^{100010311113331} is an apocalyptic number.

100010311113331 is a deficient number, since it is larger than the sum of its proper divisors (1).

100010311113331 is an equidigital number, since it uses as much as digits as its factorization.

100010311113331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 100010311113331 its reverse (133311113010001), we get a palindrome (233321424123332).

The spelling of 100010311113331 in words is "one hundred trillion, ten billion, three hundred eleven million, one hundred thirteen thousand, three hundred thirty-one".