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1000110016153 is a prime number
BaseRepresentation
bin11101000110110110011…
…00111100011010011001
310112121110101102211021101
432203123030330122121
5112341211131004103
62043235540311401
7132153441605563
oct16433314743231
93477411384241
101000110016153
11356165038736
121419b29a2561
1373405008361
1436596cc4333
151b036248a1d
hexe8db33c699

1000110016153 has 2 divisors, whose sum is σ = 1000110016154. Its totient is φ = 1000110016152.

The previous prime is 1000110016109. The next prime is 1000110016183. The reversal of 1000110016153 is 3516100110001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 922208740489 + 77901275664 = 960317^2 + 279108^2 .

It is a cyclic number.

It is not a de Polignac number, because 1000110016153 - 217 = 1000109885081 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1000110016153.

It is not a weakly prime, because it can be changed into another prime (1000110016183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500055008076 + 500055008077.

It is an arithmetic number, because the mean of its divisors is an integer number (500055008077).

Almost surely, 21000110016153 is an apocalyptic number.

It is an amenable number.

1000110016153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000110016153 is an equidigital number, since it uses as much as digits as its factorization.

1000110016153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 19.

Adding to 1000110016153 its reverse (3516100110001), we get a palindrome (4516210126154).

The spelling of 1000110016153 in words is "one trillion, one hundred ten million, sixteen thousand, one hundred fifty-three".