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10001109576713 is a prime number
BaseRepresentation
bin1001000110001001000010…
…0101010110110000001001
31022102002121112002120221012
42101202100211112300021
52302324233022423323
633134240223053305
72051361550524653
oct221422045266011
938362545076835
1010001109576713
1132064a069a472
121156347441235
1357713ccb01a8
142680b06416d3
1512524256b678
hex91890956c09

10001109576713 has 2 divisors, whose sum is σ = 10001109576714. Its totient is φ = 10001109576712.

The previous prime is 10001109576701. The next prime is 10001109576767. The reversal of 10001109576713 is 31767590110001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9970134632704 + 30974944009 = 3157552^2 + 175997^2 .

It is a cyclic number.

It is not a de Polignac number, because 10001109576713 - 24 = 10001109576697 is a prime.

It is not a weakly prime, because it can be changed into another prime (10001109546713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000554788356 + 5000554788357.

It is an arithmetic number, because the mean of its divisors is an integer number (5000554788357).

Almost surely, 210001109576713 is an apocalyptic number.

It is an amenable number.

10001109576713 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001109576713 is an equidigital number, since it uses as much as digits as its factorization.

10001109576713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 39690, while the sum is 41.

Adding to 10001109576713 its reverse (31767590110001), we get a palindrome (41768699686714).

The spelling of 10001109576713 in words is "ten trillion, one billion, one hundred nine million, five hundred seventy-six thousand, seven hundred thirteen".