Base | Representation |
---|---|
bin | 11101000110110110100… |
… | …00101111010010000011 |
3 | 10112121110110022100212121 |
4 | 32203123100233102003 |
5 | 112341211404322242 |
6 | 2043240013505111 |
7 | 132153453221056 |
oct | 16433320572203 |
9 | 3477413270777 |
10 | 1000111010947 |
11 | 356165658084 |
12 | 1419b31a2197 |
13 | 734052960a9 |
14 | 365970a2a9d |
15 | 1b036393667 |
hex | e8db42f483 |
1000111010947 has 2 divisors, whose sum is σ = 1000111010948. Its totient is φ = 1000111010946.
The previous prime is 1000111010933. The next prime is 1000111010953. The reversal of 1000111010947 is 7490101110001.
1000111010947 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1000111010947 - 231 = 997963527299 is a prime.
It is not a weakly prime, because it can be changed into another prime (1000111017947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500055505473 + 500055505474.
It is an arithmetic number, because the mean of its divisors is an integer number (500055505474).
Almost surely, 21000111010947 is an apocalyptic number.
1000111010947 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000111010947 is an equidigital number, since it uses as much as digits as its factorization.
1000111010947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 25.
Adding to 1000111010947 its reverse (7490101110001), we get a palindrome (8490212120948).
The spelling of 1000111010947 in words is "one trillion, one hundred eleven million, ten thousand, nine hundred forty-seven".
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