1000111999993 has 2 divisors, whose sum is σ = 1000111999994. Its totient is φ = 1000111999992.

The previous prime is 1000111999949. The next prime is 1000112000011. The reversal of 1000111999993 is 3999991110001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 988805505769 + 11306494224 = 994387^2 + 106332^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1000111999993 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1000111999993.

It is not a weakly prime, because it can be changed into another prime (1000111939993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500055999996 + 500055999997.

It is an arithmetic number, because the mean of its divisors is an integer number (500055999997).

Almost surely, 2^{1000111999993} is an apocalyptic number.

It is an amenable number.

1000111999993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000111999993 is an equidigital number, since it uses as much as digits as its factorization.

1000111999993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 177147, while the sum is 52.

The spelling of 1000111999993 in words is "one trillion, one hundred eleven million, nine hundred ninety-nine thousand, nine hundred ninety-three".