1000120019993 has 2 divisors, whose sum is σ = 1000120019994. Its totient is φ = 1000120019992.

The previous prime is 1000120019957. The next prime is 1000120020001. The reversal of 1000120019993 is 3999100210001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 765954035344 + 234165984649 = 875188^2 + 483907^2 .

It is a cyclic number.

It is not a de Polignac number, because 1000120019993 - 2¹⁰ = 1000120018969 is a prime.

It is not a weakly prime, because it can be changed into another prime (1000120019903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500060009996 + 500060009997.

It is an arithmetic number, because the mean of its divisors is an integer number (500060009997).

Almost surely, 2^{1000120019993} is an apocalyptic number.

It is an amenable number.

1000120019993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000120019993 is an equidigital number, since it uses as much as digits as its factorization.

1000120019993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4374, while the sum is 35.

Adding to 1000120019993 its reverse (3999100210001), we get a palindrome (4999220229994).

The spelling of 1000120019993 in words is "one trillion, one hundred twenty million, nineteen thousand, nine hundred ninety-three".