Base | Representation |
---|---|
bin | 101110100100100101… |
… | …1100010111010111001 |
3 | 100120011000020120111201 |
4 | 1131021023202322321 |
5 | 3114311033324233 |
6 | 113540032254201 |
7 | 10140251032363 |
oct | 1351113427271 |
9 | 316130216451 |
10 | 100012011193 |
11 | 3946219a306 |
12 | 174719a1361 |
13 | 957b156863 |
14 | 4baa8a9d33 |
15 | 290530d77d |
hex | 17492e2eb9 |
100012011193 has 2 divisors, whose sum is σ = 100012011194. Its totient is φ = 100012011192.
The previous prime is 100012011163. The next prime is 100012011271. The reversal of 100012011193 is 391110210001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98996441769 + 1015569424 = 314637^2 + 31868^2 .
It is a cyclic number.
It is not a de Polignac number, because 100012011193 - 25 = 100012011161 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 100012011193.
It is not a weakly prime, because it can be changed into another prime (100012011133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50006005596 + 50006005597.
It is an arithmetic number, because the mean of its divisors is an integer number (50006005597).
Almost surely, 2100012011193 is an apocalyptic number.
It is an amenable number.
100012011193 is a deficient number, since it is larger than the sum of its proper divisors (1).
100012011193 is an equidigital number, since it uses as much as digits as its factorization.
100012011193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 100012011193 its reverse (391110210001), we get a palindrome (491122221194).
The spelling of 100012011193 in words is "one hundred billion, twelve million, eleven thousand, one hundred ninety-three".
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