Base | Representation |
---|---|
bin | 101110100100100110… |
… | …0010011011111010011 |
3 | 100120011000121200101210 |
4 | 1131021030103133103 |
5 | 3114311111211011 |
6 | 113540040431203 |
7 | 10140252521361 |
oct | 1351114233723 |
9 | 316130550353 |
10 | 100012210131 |
11 | 39462315819 |
12 | 17471a78503 |
13 | 957b1c6282 |
14 | 4baa91c631 |
15 | 290534c6a6 |
hex | 17493137d3 |
100012210131 has 4 divisors (see below), whose sum is σ = 133349613512. Its totient is φ = 66674806752.
The previous prime is 100012210091. The next prime is 100012210139. The reversal of 100012210131 is 131012210001.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 100012210131 - 211 = 100012208083 is a prime.
It is a super-2 number, since 2×1000122101312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (100012210139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16668701686 + ... + 16668701691.
It is an arithmetic number, because the mean of its divisors is an integer number (33337403378).
Almost surely, 2100012210131 is an apocalyptic number.
100012210131 is a deficient number, since it is larger than the sum of its proper divisors (33337403381).
100012210131 is an equidigital number, since it uses as much as digits as its factorization.
100012210131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33337403380.
The product of its (nonzero) digits is 12, while the sum is 12.
Adding to 100012210131 its reverse (131012210001), we get a palindrome (231024420132).
The spelling of 100012210131 in words is "one hundred billion, twelve million, two hundred ten thousand, one hundred thirty-one".
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