Base | Representation |
---|---|
bin | 10110101111010111101000… |
… | …010100010010100000011001 |
3 | 111010010001222221200201001002 |
4 | 112233113220110102200121 |
5 | 101102100002021321103 |
6 | 552412550413234345 |
7 | 30031433553016523 |
oct | 2657275024224031 |
9 | 433101887621032 |
10 | 100012211120153 |
11 | 29959a38956512 |
12 | b2730531929b5 |
13 | 43a6159c59427 |
14 | 1a9a88c8a8a13 |
15 | b86831844488 |
hex | 5af5e8512819 |
100012211120153 has 2 divisors, whose sum is σ = 100012211120154. Its totient is φ = 100012211120152.
The previous prime is 100012211120147. The next prime is 100012211120167. The reversal of 100012211120153 is 351021112210001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 79624069325824 + 20388141794329 = 8923232^2 + 4515323^2 .
It is a cyclic number.
It is not a de Polignac number, because 100012211120153 - 214 = 100012211103769 is a prime.
It is not a weakly prime, because it can be changed into another prime (100012211120753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50006105560076 + 50006105560077.
It is an arithmetic number, because the mean of its divisors is an integer number (50006105560077).
Almost surely, 2100012211120153 is an apocalyptic number.
It is an amenable number.
100012211120153 is a deficient number, since it is larger than the sum of its proper divisors (1).
100012211120153 is an equidigital number, since it uses as much as digits as its factorization.
100012211120153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 20.
Adding to 100012211120153 its reverse (351021112210001), we get a palindrome (451033323330154).
The spelling of 100012211120153 in words is "one hundred trillion, twelve billion, two hundred eleven million, one hundred twenty thousand, one hundred fifty-three".
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