Base | Representation |
---|---|
bin | 10110101111010111101001… |
… | …100011111100010111000011 |
3 | 111010010002001101222120010102 |
4 | 112233113221203330113003 |
5 | 101102100022343012323 |
6 | 552412552440553015 |
7 | 30031434225344522 |
oct | 2657275143742703 |
9 | 433102041876112 |
10 | 100012232000963 |
11 | 29959a49718587 |
12 | b27305a18276b |
13 | 43a616138a739 |
14 | 1a9a8915824b9 |
15 | b868335bb328 |
hex | 5af5e98fc5c3 |
100012232000963 has 2 divisors, whose sum is σ = 100012232000964. Its totient is φ = 100012232000962.
The previous prime is 100012232000927. The next prime is 100012232001013. The reversal of 100012232000963 is 369000232210001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100012232000963 - 218 = 100012231738819 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (100012232000563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50006116000481 + 50006116000482.
It is an arithmetic number, because the mean of its divisors is an integer number (50006116000482).
Almost surely, 2100012232000963 is an apocalyptic number.
100012232000963 is a deficient number, since it is larger than the sum of its proper divisors (1).
100012232000963 is an equidigital number, since it uses as much as digits as its factorization.
100012232000963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 29.
Adding to 100012232000963 its reverse (369000232210001), we get a palindrome (469012464210964).
The spelling of 100012232000963 in words is "one hundred trillion, twelve billion, two hundred thirty-two million, nine hundred sixty-three", and thus it is an aban number.
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