Base | Representation |
---|---|
bin | 11101000110111001001… |
… | …01000000100110111101 |
3 | 10112121111222212201010020 |
4 | 32203130211000212331 |
5 | 112341233033231023 |
6 | 2043242123202353 |
7 | 132154142046363 |
oct | 16433445004675 |
9 | 3477458781106 |
10 | 1000133102013 |
11 | 356177076461 |
12 | 1419ba6763b9 |
13 | 73409a2c226 |
14 | 36599db3633 |
15 | 1b0382a8de3 |
hex | e8dc9409bd |
1000133102013 has 32 divisors (see below), whose sum is σ = 1370295843840. Its totient is φ = 648467189760.
The previous prime is 1000133101993. The next prime is 1000133102039. The reversal of 1000133102013 is 3102013310001.
1000133102013 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 1000133102013 - 222 = 1000128907709 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1000133101983 and 1000133102001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1000133102083) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 60853045 + ... + 60869477.
It is an arithmetic number, because the mean of its divisors is an integer number (42821745120).
Almost surely, 21000133102013 is an apocalyptic number.
It is an amenable number.
1000133102013 is a deficient number, since it is larger than the sum of its proper divisors (370162741827).
1000133102013 is a wasteful number, since it uses less digits than its factorization.
1000133102013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17989.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 1000133102013 its reverse (3102013310001), we get a palindrome (4102146412014).
The spelling of 1000133102013 in words is "one trillion, one hundred thirty-three million, one hundred two thousand, thirteen".
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