Base | Representation |
---|---|
bin | 11101000111000001011… |
… | …11101010010011101001 |
3 | 10112121200212102001101212 |
4 | 32203200233222103221 |
5 | 112341403432044423 |
6 | 2043253101322505 |
7 | 132155651151566 |
oct | 16434057522351 |
9 | 3477625361355 |
10 | 1000203003113 |
11 | 35620257a166 |
12 | 141a19b66435 |
13 | 7341b364a22 |
14 | 365a53ab86d |
15 | 1b03e4b5578 |
hex | e8e0bea4e9 |
1000203003113 has 2 divisors, whose sum is σ = 1000203003114. Its totient is φ = 1000203003112.
The previous prime is 1000203003101. The next prime is 1000203003119. The reversal of 1000203003113 is 3113003020001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 999306120409 + 896882704 = 999653^2 + 29948^2 .
It is a cyclic number.
It is not a de Polignac number, because 1000203003113 - 24 = 1000203003097 is a prime.
It is not a weakly prime, because it can be changed into another prime (1000203003119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500101501556 + 500101501557.
It is an arithmetic number, because the mean of its divisors is an integer number (500101501557).
Almost surely, 21000203003113 is an apocalyptic number.
It is an amenable number.
1000203003113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000203003113 is an equidigital number, since it uses as much as digits as its factorization.
1000203003113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 1000203003113 its reverse (3113003020001), we get a palindrome (4113206023114).
The spelling of 1000203003113 in words is "one trillion, two hundred three million, three thousand, one hundred thirteen".
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