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100021132121 is a prime number
BaseRepresentation
bin101110100100110111…
…0010101101101011001
3100120011122101222001212
41131021232111231121
53114320402211441
6113540555552505
710140421411121
oct1351156255531
9316148358055
10100021132121
1139467359a69
1217474a5b735
13957cccb261
144babba1c81
152906010eeb
hex1749b95b59

100021132121 has 2 divisors, whose sum is σ = 100021132122. Its totient is φ = 100021132120.

The previous prime is 100021132111. The next prime is 100021132129. The reversal of 100021132121 is 121231120001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91660590025 + 8360542096 = 302755^2 + 91436^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100021132121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100021132096 and 100021132105.

It is not a weakly prime, because it can be changed into another prime (100021132129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50010566060 + 50010566061.

It is an arithmetic number, because the mean of its divisors is an integer number (50010566061).

Almost surely, 2100021132121 is an apocalyptic number.

It is an amenable number.

100021132121 is a deficient number, since it is larger than the sum of its proper divisors (1).

100021132121 is an equidigital number, since it uses as much as digits as its factorization.

100021132121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 100021132121 its reverse (121231120001), we get a palindrome (221252252122).

The spelling of 100021132121 in words is "one hundred billion, twenty-one million, one hundred thirty-two thousand, one hundred twenty-one".