Base | Representation |
---|---|
bin | 10010101000010110… |
… | …00011110110111011 |
3 | 221211001202100101110 |
4 | 21110023003312323 |
5 | 130441020320443 |
6 | 4332300051403 |
7 | 502601422032 |
oct | 112413036673 |
9 | 27731670343 |
10 | 10002120123 |
11 | 4272a32986 |
12 | 1b31833b63 |
13 | c35280498 |
14 | 6ac555719 |
15 | 3d817b233 |
hex | 2542c3dbb |
10002120123 has 4 divisors (see below), whose sum is σ = 13336160168. Its totient is φ = 6668080080.
The previous prime is 10002120113. The next prime is 10002120133. The reversal of 10002120123 is 32102120001.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (10002120113) and next prime (10002120133).
It is not a de Polignac number, because 10002120123 - 221 = 10000022971 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10002120099 and 10002120108.
It is not an unprimeable number, because it can be changed into a prime (10002120113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1667020018 + ... + 1667020023.
It is an arithmetic number, because the mean of its divisors is an integer number (3334040042).
Almost surely, 210002120123 is an apocalyptic number.
10002120123 is a deficient number, since it is larger than the sum of its proper divisors (3334040045).
10002120123 is an equidigital number, since it uses as much as digits as its factorization.
10002120123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3334040044.
The product of its (nonzero) digits is 24, while the sum is 12.
Adding to 10002120123 its reverse (32102120001), we get a palindrome (42104240124).
The spelling of 10002120123 in words is "ten billion, two million, one hundred twenty thousand, one hundred twenty-three".
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