Base | Representation |
---|---|
bin | 1001000110001101111101… |
… | …0111011111000111111011 |
3 | 1022102020000122020011201221 |
4 | 2101203133113133013323 |
5 | 2302334434410403201 |
6 | 33135015321052511 |
7 | 2051436400403212 |
oct | 221433727370773 |
9 | 38366018204657 |
10 | 10002431341051 |
11 | 3207009802596 |
12 | 1156656027137 |
13 | 5772c0a98676 |
14 | 268197dca079 |
15 | 1252bd60a4a1 |
hex | 918df5df1fb |
10002431341051 has 2 divisors, whose sum is σ = 10002431341052. Its totient is φ = 10002431341050.
The previous prime is 10002431341013. The next prime is 10002431341081. The reversal of 10002431341051 is 15014313420001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10002431341051 is a prime.
It is not a weakly prime, because it can be changed into another prime (10002431341081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001215670525 + 5001215670526.
It is an arithmetic number, because the mean of its divisors is an integer number (5001215670526).
Almost surely, 210002431341051 is an apocalyptic number.
10002431341051 is a deficient number, since it is larger than the sum of its proper divisors (1).
10002431341051 is an equidigital number, since it uses as much as digits as its factorization.
10002431341051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 10002431341051 its reverse (15014313420001), we get a palindrome (25016744761052).
The spelling of 10002431341051 in words is "ten trillion, two billion, four hundred thirty-one million, three hundred forty-one thousand, fifty-one".
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