Base | Representation |
---|---|
bin | 1001000110010000100001… |
… | …1111001000001010000011 |
3 | 1022102021210201100011000021 |
4 | 2101210020133020022003 |
5 | 2302342343012204422 |
6 | 33135212003234311 |
7 | 2051462445241003 |
oct | 221441037101203 |
9 | 38367721304007 |
10 | 10003121209987 |
11 | 3207333162304 |
12 | 1156809078997 |
13 | 5773a099b639 |
14 | 268221888003 |
15 | 12530de7adc7 |
hex | 919087c8283 |
10003121209987 has 2 divisors, whose sum is σ = 10003121209988. Its totient is φ = 10003121209986.
The previous prime is 10003121209969. The next prime is 10003121210011. The reversal of 10003121209987 is 78990212130001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10003121209987 - 27 = 10003121209859 is a prime.
It is not a weakly prime, because it can be changed into another prime (10003121209927) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001560604993 + 5001560604994.
It is an arithmetic number, because the mean of its divisors is an integer number (5001560604994).
Almost surely, 210003121209987 is an apocalyptic number.
10003121209987 is a deficient number, since it is larger than the sum of its proper divisors (1).
10003121209987 is an equidigital number, since it uses as much as digits as its factorization.
10003121209987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 43.
Adding to 10003121209987 its reverse (78990212130001), we get a palindrome (88993333339988).
The spelling of 10003121209987 in words is "ten trillion, three billion, one hundred twenty-one million, two hundred nine thousand, nine hundred eighty-seven".
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