1000314221113 has 2 divisors, whose sum is σ = 1000314221114. Its totient is φ = 1000314221112.

The previous prime is 1000314221069. The next prime is 1000314221161. The reversal of 1000314221113 is 3111224130001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 940098950569 + 60215270544 = 969587^2 + 245388^2 .

It is a cyclic number.

It is not a de Polignac number, because 1000314221113 - 2⁹ = 1000314220601 is a prime.

It is a super-3 number, since 3×1000314221113³ (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1000314221183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500157110556 + 500157110557.

It is an arithmetic number, because the mean of its divisors is an integer number (500157110557).

Almost surely, 2^{1000314221113} is an apocalyptic number.

It is an amenable number.

1000314221113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000314221113 is an equidigital number, since it uses as much as digits as its factorization.

1000314221113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1000314221113 its reverse (3111224130001), we get a palindrome (4111538351114).

The spelling of 1000314221113 in words is "one trillion, three hundred fourteen million, two hundred twenty-one thousand, one hundred thirteen".