100032019 has 2 divisors, whose sum is σ = 100032020. Its totient is φ = 100032018.

The previous prime is 100032011. The next prime is 100032059. The reversal of 100032019 is 910230001.

It is a weak prime.

It is an emirp because it is prime and its reverse (910230001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100032019 - 2³ = 100032011 is a prime.

It is a super-2 number, since 2×100032019² = 20012809650432722, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100031993 and 100032011.

It is not a weakly prime, because it can be changed into another prime (100032011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50016009 + 50016010.

It is an arithmetic number, because the mean of its divisors is an integer number (50016010).

Almost surely, 2^100032019 is an apocalyptic number.

100032019 is a deficient number, since it is larger than the sum of its proper divisors (1).

100032019 is an equidigital number, since it uses as much as digits as its factorization.

100032019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

The square root of 100032019 is about 10001.6008218685. The cubic root of 100032019 is about 464.2084177525.

The spelling of 100032019 in words is "one hundred million, thirty-two thousand, nineteen".