Base | Representation |
---|---|
bin | 10010101000011111… |
… | …00111000111101011 |
3 | 221211010222221212221 |
4 | 21110033213013223 |
5 | 130441322010011 |
6 | 4332341414511 |
7 | 502614521140 |
oct | 112417470753 |
9 | 27733887787 |
10 | 10003313131 |
11 | 4273678239 |
12 | 1b3210a437 |
13 | c355aa4c6 |
14 | 6ac7863c7 |
15 | 3d8314971 |
hex | 2543e71eb |
10003313131 has 4 divisors (see below), whose sum is σ = 11432357872. Its totient is φ = 8574268392.
The previous prime is 10003313129. The next prime is 10003313161. The reversal of 10003313131 is 13131330001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10003313131 - 21 = 10003313129 is a prime.
It is a super-2 number, since 2×100033131312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10003313161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 714522360 + ... + 714522373.
It is an arithmetic number, because the mean of its divisors is an integer number (2858089468).
Almost surely, 210003313131 is an apocalyptic number.
10003313131 is a deficient number, since it is larger than the sum of its proper divisors (1429044741).
10003313131 is an equidigital number, since it uses as much as digits as its factorization.
10003313131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1429044740.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 10003313131 its reverse (13131330001), we get a palindrome (23134643132).
The spelling of 10003313131 in words is "ten billion, three million, three hundred thirteen thousand, one hundred thirty-one".
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