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10003321113 = 33334440371
BaseRepresentation
bin10010101000011111…
…01001000100011001
3221211011000100211120
421110033221010121
5130441322233423
64332341515453
7502614553332
oct112417510431
927734010746
1010003321113
114273683235
121b32112b89
13c355b1026
146ac789289
153d8316ee3
hex2543e9119

10003321113 has 4 divisors (see below), whose sum is σ = 13337761488. Its totient is φ = 6668880740.

The previous prime is 10003321099. The next prime is 10003321123. The reversal of 10003321113 is 31112330001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10003321113 - 28 = 10003320857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10003321092 and 10003321101.

It is not an unprimeable number, because it can be changed into a prime (10003321123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1667220183 + ... + 1667220188.

It is an arithmetic number, because the mean of its divisors is an integer number (3334440372).

Almost surely, 210003321113 is an apocalyptic number.

It is an amenable number.

10003321113 is a deficient number, since it is larger than the sum of its proper divisors (3334440375).

10003321113 is an equidigital number, since it uses as much as digits as its factorization.

10003321113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3334440374.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10003321113 its reverse (31112330001), we get a palindrome (41115651114).

The spelling of 10003321113 in words is "ten billion, three million, three hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 3 3334440371 10003321113