Base | Representation |
---|---|
bin | 101110100101001111… |
… | …1100101111000101001 |
3 | 100120012112200221001121 |
4 | 1131022133211320221 |
5 | 3114332203342213 |
6 | 113542140415241 |
7 | 10140636224332 |
oct | 1351237457051 |
9 | 316175627047 |
10 | 100034043433 |
11 | 39473678475 |
12 | 17479247521 |
13 | 958289bc9c |
14 | 4bad7a3289 |
15 | 290721188d |
hex | 174a7e5e29 |
100034043433 has 2 divisors, whose sum is σ = 100034043434. Its totient is φ = 100034043432.
The previous prime is 100034043427. The next prime is 100034043443. The reversal of 100034043433 is 334340430001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 94296283929 + 5737759504 = 307077^2 + 75748^2 .
It is a cyclic number.
It is not a de Polignac number, because 100034043433 - 25 = 100034043401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100034043398 and 100034043407.
It is not a weakly prime, because it can be changed into another prime (100034043443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50017021716 + 50017021717.
It is an arithmetic number, because the mean of its divisors is an integer number (50017021717).
Almost surely, 2100034043433 is an apocalyptic number.
It is an amenable number.
100034043433 is a deficient number, since it is larger than the sum of its proper divisors (1).
100034043433 is an equidigital number, since it uses as much as digits as its factorization.
100034043433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 100034043433 its reverse (334340430001), we get a palindrome (434374473434).
The spelling of 100034043433 in words is "one hundred billion, thirty-four million, forty-three thousand, four hundred thirty-three".
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