10003413403 has 4 divisors (see below), whose sum is σ = 10236050968. Its totient is φ = 9770775840.

The previous prime is 10003413383. The next prime is 10003413419. The reversal of 10003413403 is 30431430001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10003413403 - 2⁹ = 10003412891 is a prime.

It is a super-2 number, since 2×10003413403² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10003413443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116318718 + ... + 116318803.

It is an arithmetic number, because the mean of its divisors is an integer number (2559012742).

Almost surely, 2^10003413403 is an apocalyptic number.

10003413403 is a deficient number, since it is larger than the sum of its proper divisors (232637565).

10003413403 is an equidigital number, since it uses as much as digits as its factorization.

10003413403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 232637564.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 10003413403 its reverse (30431430001), we get a palindrome (40434843404).

The spelling of 10003413403 in words is "ten billion, three million, four hundred thirteen thousand, four hundred three".