100034313 has 4 divisors (see below), whose sum is σ = 133379088. Its totient is φ = 66689540.

The previous prime is 100034281. The next prime is 100034317. The reversal of 100034313 is 313430001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 313430001 = 3 ⋅104476667.

It is a cyclic number.

It is not a de Polignac number, because 100034313 - 2⁵ = 100034281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100034292 and 100034301.

It is not an unprimeable number, because it can be changed into a prime (100034317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16672383 + ... + 16672388.

It is an arithmetic number, because the mean of its divisors is an integer number (33344772).

Almost surely, 2^100034313 is an apocalyptic number.

It is an amenable number.

100034313 is a deficient number, since it is larger than the sum of its proper divisors (33344775).

100034313 is an equidigital number, since it uses as much as digits as its factorization.

100034313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33344774.

The product of its (nonzero) digits is 108, while the sum is 15.

The square root of 100034313 is about 10001.7155028525. The cubic root of 100034313 is about 464.2119662362.

Adding to 100034313 its reverse (313430001), we get a palindrome (413464314).

The spelling of 100034313 in words is "one hundred million, thirty-four thousand, three hundred thirteen".