10003550121 has 12 divisors (see below), whose sum is σ = 14451348340. Its totient is φ = 6668213760.

The previous prime is 10003550113. The next prime is 10003550131. The reversal of 10003550121 is 12105530001.

10003550121 is a `hidden beast` number, since 100 + 0 + 3 + 550 + 12 + 1 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 7893434025 + 2110116096 = 88845^2 + 45936^2 .

It is not a de Polignac number, because 10003550121 - 2³ = 10003550113 is a prime.

It is a super-3 number, since 3×10003550121³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10003550094 and 10003550103.

It is not an unprimeable number, because it can be changed into a prime (10003550111) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 14241 + ... + 142161.

Almost surely, 2^10003550121 is an apocalyptic number.

It is an amenable number.

10003550121 is a deficient number, since it is larger than the sum of its proper divisors (4447798219).

10003550121 is a wasteful number, since it uses less digits than its factorization.

10003550121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 136616 (or 136613 counting only the distinct ones).

The product of its (nonzero) digits is 150, while the sum is 18.

The spelling of 10003550121 in words is "ten billion, three million, five hundred fifty thousand, one hundred twenty-one".