Search a number
-
+
100040213011147 is a prime number
BaseRepresentation
bin10110101111110001101101…
…010111000001101011001011
3111010012202021110012011010221
4112233301231113001223023
5101103024324012324042
6552433501151050511
730033444511120633
oct2657615527015313
9433182243164127
10100040213011147
112996a8a8224692
12b278568b10a37
1343a89a0389ab6
141a9bd877cb6c3
15b8741ed30d67
hex5afc6d5c1acb

100040213011147 has 2 divisors, whose sum is σ = 100040213011148. Its totient is φ = 100040213011146.

The previous prime is 100040213011091. The next prime is 100040213011163. The reversal of 100040213011147 is 741110312040001.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100040213011147 is a prime.

It is a super-3 number, since 3×1000402130111473 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (100040213011747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50020106505573 + 50020106505574.

It is an arithmetic number, because the mean of its divisors is an integer number (50020106505574).

Almost surely, 2100040213011147 is an apocalyptic number.

100040213011147 is a deficient number, since it is larger than the sum of its proper divisors (1).

100040213011147 is an equidigital number, since it uses as much as digits as its factorization.

100040213011147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 672, while the sum is 25.

Adding to 100040213011147 its reverse (741110312040001), we get a palindrome (841150525051148).

The spelling of 100040213011147 in words is "one hundred trillion, forty billion, two hundred thirteen million, eleven thousand, one hundred forty-seven".