Search a number
-
+
100043313 = 333347771
BaseRepresentation
bin1011111011010…
…00101000110001
320222020201121220
411331220220301
5201102341223
613532135253
72323232316
oct575505061
9228221556
10100043313
1151521027
1229607529
131795a436
14d402d0d
158bb26e3
hex5f68a31

100043313 has 4 divisors (see below), whose sum is σ = 133391088. Its totient is φ = 66695540.

The previous prime is 100043311. The next prime is 100043347. The reversal of 100043313 is 313340001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100043313 - 21 = 100043311 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100043292 and 100043301.

It is not an unprimeable number, because it can be changed into a prime (100043311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16673883 + ... + 16673888.

It is an arithmetic number, because the mean of its divisors is an integer number (33347772).

Almost surely, 2100043313 is an apocalyptic number.

It is an amenable number.

100043313 is a deficient number, since it is larger than the sum of its proper divisors (33347775).

100043313 is an equidigital number, since it uses as much as digits as its factorization.

100043313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33347774.

The product of its (nonzero) digits is 108, while the sum is 15.

The square root of 100043313 is about 10002.1654155488. The cubic root of 100043313 is about 464.2258874008.

Adding to 100043313 its reverse (313340001), we get a palindrome (413383314).

The spelling of 100043313 in words is "one hundred million, forty-three thousand, three hundred thirteen".

Divisors: 1 3 33347771 100043313