10004402414131 has 2 divisors, whose sum is σ = 10004402414132. Its totient is φ = 10004402414130.

The previous prime is 10004402414119. The next prime is 10004402414147. The reversal of 10004402414131 is 13141420440001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10004402414131 - 2²¹ = 10004400316979 is a prime.

It is a super-2 number, since 2×10004402414131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10004402414096 and 10004402414105.

It is not a weakly prime, because it can be changed into another prime (10004400414131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002201207065 + 5002201207066.

It is an arithmetic number, because the mean of its divisors is an integer number (5002201207066).

Almost surely, 2^{10004402414131} is an apocalyptic number.

10004402414131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10004402414131 is an equidigital number, since it uses as much as digits as its factorization.

10004402414131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 10004402414131 its reverse (13141420440001), we get a palindrome (23145822854132).

The spelling of 10004402414131 in words is "ten trillion, four billion, four hundred two million, four hundred fourteen thousand, one hundred thirty-one".