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10004411340241 is a prime number
BaseRepresentation
bin1001000110010101010101…
…1000100101010111010001
31022102102010121221120000021
42101211111120211113101
52302403013300341431
633135544011223441
72051536432203463
oct221452530452721
938372117846007
1010004411340241
11320793542925a
121156b09147b81
1357754805c116
14268304d5a133
1512538736bb11
hex919556255d1

10004411340241 has 2 divisors, whose sum is σ = 10004411340242. Its totient is φ = 10004411340240.

The previous prime is 10004411340227. The next prime is 10004411340247. The reversal of 10004411340241 is 14204311440001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9051649891216 + 952761449025 = 3008596^2 + 976095^2 .

It is a cyclic number.

It is not a de Polignac number, because 10004411340241 - 27 = 10004411340113 is a prime.

It is not a weakly prime, because it can be changed into another prime (10004411340247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002205670120 + 5002205670121.

It is an arithmetic number, because the mean of its divisors is an integer number (5002205670121).

Almost surely, 210004411340241 is an apocalyptic number.

It is an amenable number.

10004411340241 is a deficient number, since it is larger than the sum of its proper divisors (1).

10004411340241 is an equidigital number, since it uses as much as digits as its factorization.

10004411340241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 10004411340241 its reverse (14204311440001), we get a palindrome (24208722780242).

The spelling of 10004411340241 in words is "ten trillion, four billion, four hundred eleven million, three hundred forty thousand, two hundred forty-one".