100053113 has 2 divisors, whose sum is σ = 100053114. Its totient is φ = 100053112.

The previous prime is 100053091. The next prime is 100053119. The reversal of 100053113 is 311350001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61277584 + 38775529 = 7828^2 + 6227^2 .

It is an emirp because it is prime and its reverse (311350001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100053113 - 2⁸ = 100052857 is a prime.

It is not a weakly prime, because it can be changed into another prime (100053119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50026556 + 50026557.

It is an arithmetic number, because the mean of its divisors is an integer number (50026557).

Almost surely, 2^100053113 is an apocalyptic number.

It is an amenable number.

100053113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100053113 is an equidigital number, since it uses as much as digits as its factorization.

100053113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45, while the sum is 14.

The square root of 100053113 is about 10002.6552974698. The cubic root of 100053113 is about 464.2410450527.

The spelling of 100053113 in words is "one hundred million, fifty-three thousand, one hundred thirteen".