100054113 has 4 divisors (see below), whose sum is σ = 133405488. Its totient is φ = 66702740.

The previous prime is 100054111. The next prime is 100054121. The reversal of 100054113 is 311450001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311450001 = 3 ⋅103816667.

It is a cyclic number.

It is not a de Polignac number, because 100054113 - 2¹ = 100054111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100054092 and 100054101.

It is not an unprimeable number, because it can be changed into a prime (100054111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16675683 + ... + 16675688.

It is an arithmetic number, because the mean of its divisors is an integer number (33351372).

Almost surely, 2^100054113 is an apocalyptic number.

It is an amenable number.

100054113 is a deficient number, since it is larger than the sum of its proper divisors (33351375).

100054113 is an equidigital number, since it uses as much as digits as its factorization.

100054113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33351374.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 100054113 is about 10002.7052840719. The cubic root of 100054113 is about 464.2425916962.

The spelling of 100054113 in words is "one hundred million, fifty-four thousand, one hundred thirteen".