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100064754614753 is a prime number
BaseRepresentation
bin10110110000001000100100…
…001001110100000111100001
3111010022002121210112210022122
4112300020210021310013201
5101103430104140133003
6552453040314514025
730035303621242445
oct2660104411640741
9433262553483278
10100064754614753
112997a25132a715
12b281277a35915
1343ab0b1946936
141a9d234d2c825
15b87da9657238
hex5b02242741e1

100064754614753 has 2 divisors, whose sum is σ = 100064754614754. Its totient is φ = 100064754614752.

The previous prime is 100064754614663. The next prime is 100064754614767. The reversal of 100064754614753 is 357416457460001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94992858759184 + 5071895855569 = 9746428^2 + 2252087^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100064754614753 is a prime.

It is a super-2 number, since 2×1000647546147532 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100064754614695 and 100064754614704.

It is not a weakly prime, because it can be changed into another prime (100064754614653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50032377307376 + 50032377307377.

It is an arithmetic number, because the mean of its divisors is an integer number (50032377307377).

Almost surely, 2100064754614753 is an apocalyptic number.

It is an amenable number.

100064754614753 is a deficient number, since it is larger than the sum of its proper divisors (1).

100064754614753 is an equidigital number, since it uses as much as digits as its factorization.

100064754614753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8467200, while the sum is 53.

The spelling of 100064754614753 in words is "one hundred trillion, sixty-four billion, seven hundred fifty-four million, six hundred fourteen thousand, seven hundred fifty-three".