Base | Representation |
---|---|
bin | 1001000110011110010010… |
… | …0001111101111011000001 |
3 | 1022102122022222222120022012 |
4 | 2101213210201331323001 |
5 | 2302422423103121032 |
6 | 33141022202022305 |
7 | 2051653103401103 |
oct | 221474441757301 |
9 | 38378288876265 |
10 | 10006812942017 |
11 | 3208958035211 |
12 | 11574794a7995 |
13 | 57783b788b68 |
14 | 268491cb5573 |
15 | 12547810c6b2 |
hex | 919e487dec1 |
10006812942017 has 2 divisors, whose sum is σ = 10006812942018. Its totient is φ = 10006812942016.
The previous prime is 10006812941999. The next prime is 10006812942079. The reversal of 10006812942017 is 71024921860001.
10006812942017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8650633910416 + 1356179031601 = 2941196^2 + 1164551^2 .
It is an emirp because it is prime and its reverse (71024921860001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10006812942017 - 218 = 10006812679873 is a prime.
It is not a weakly prime, because it can be changed into another prime (10006812942517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5003406471008 + 5003406471009.
It is an arithmetic number, because the mean of its divisors is an integer number (5003406471009).
Almost surely, 210006812942017 is an apocalyptic number.
It is an amenable number.
10006812942017 is a deficient number, since it is larger than the sum of its proper divisors (1).
10006812942017 is an equidigital number, since it uses as much as digits as its factorization.
10006812942017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 41.
The spelling of 10006812942017 in words is "ten trillion, six billion, eight hundred twelve million, nine hundred forty-two thousand, seventeen".
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