Base | Representation |
---|---|
bin | 10110110000101001011111… |
… | …000000010010101001100011 |
3 | 111010102110212012100101211102 |
4 | 112300221133000102221203 |
5 | 101110020002014244413 |
6 | 552521204001505015 |
7 | 30040664556514505 |
oct | 2660513700225143 |
9 | 433373765311742 |
10 | 100100101712483 |
11 | 2999323a8a3384 |
12 | b2880a164216b |
13 | 43b1525a48792 |
14 | 1aa0c2958bd75 |
15 | b88c778eb458 |
hex | 5b0a5f012a63 |
100100101712483 has 2 divisors, whose sum is σ = 100100101712484. Its totient is φ = 100100101712482.
The previous prime is 100100101712473. The next prime is 100100101712509. The reversal of 100100101712483 is 384217101001001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100100101712483 - 28 = 100100101712227 is a prime.
It is not a weakly prime, because it can be changed into another prime (100100101712473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050050856241 + 50050050856242.
It is an arithmetic number, because the mean of its divisors is an integer number (50050050856242).
Almost surely, 2100100101712483 is an apocalyptic number.
100100101712483 is a deficient number, since it is larger than the sum of its proper divisors (1).
100100101712483 is an equidigital number, since it uses as much as digits as its factorization.
100100101712483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 29.
Adding to 100100101712483 its reverse (384217101001001), we get a palindrome (484317202713484).
The spelling of 100100101712483 in words is "one hundred trillion, one hundred billion, one hundred one million, seven hundred twelve thousand, four hundred eighty-three".
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