1001012121217 has 2 divisors, whose sum is σ = 1001012121218. Its totient is φ = 1001012121216.

The previous prime is 1001012121181. The next prime is 1001012121257. The reversal of 1001012121217 is 7121212101001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 518631865921 + 482380255296 = 720161^2 + 694536^2 .

It is an emirp because it is prime and its reverse (7121212101001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1001012121217 - 2¹⁵ = 1001012088449 is a prime.

It is a super-3 number, since 3×1001012121217³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1001012121194 and 1001012121203.

It is not a weakly prime, because it can be changed into another prime (1001012121257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500506060608 + 500506060609.

It is an arithmetic number, because the mean of its divisors is an integer number (500506060609).

Almost surely, 2^{1001012121217} is an apocalyptic number.

It is an amenable number.

1001012121217 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001012121217 is an equidigital number, since it uses as much as digits as its factorization.

1001012121217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 1001012121217 its reverse (7121212101001), we get a palindrome (8122224222218).

The spelling of 1001012121217 in words is "one trillion, one billion, twelve million, one hundred twenty-one thousand, two hundred seventeen".