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1001022121993 is a prime number
BaseRepresentation
bin11101001000100011001…
…00010110100000001001
310112200210221201121021011
432210101210112200021
5112400043130400433
62043510242043521
7132215155434355
oct16442144264011
93480727647234
101001022121993
11356592989313
121420083495a1
137351bc7cc5a
14366420b2465
151b08b3673cd
hexe911916809

1001022121993 has 2 divisors, whose sum is σ = 1001022121994. Its totient is φ = 1001022121992.

The previous prime is 1001022121951. The next prime is 1001022122041. The reversal of 1001022121993 is 3991212201001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 745827413769 + 255194708224 = 863613^2 + 505168^2 .

It is an emirp because it is prime and its reverse (3991212201001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1001022121993 is a prime.

It is not a weakly prime, because it can be changed into another prime (1001022121943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500511060996 + 500511060997.

It is an arithmetic number, because the mean of its divisors is an integer number (500511060997).

Almost surely, 21001022121993 is an apocalyptic number.

It is an amenable number.

1001022121993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001022121993 is an equidigital number, since it uses as much as digits as its factorization.

1001022121993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 31.

Adding to 1001022121993 its reverse (3991212201001), we get a palindrome (4992234322994).

The spelling of 1001022121993 in words is "one trillion, one billion, twenty-two million, one hundred twenty-one thousand, nine hundred ninety-three".