Base | Representation |
---|---|
bin | 1001000110101011000110… |
… | …1101001100001100101001 |
3 | 1022102222012220020001212011 |
4 | 2101222301231030030221 |
5 | 2303002000313311403 |
6 | 33142351525515521 |
7 | 2052134312253433 |
oct | 221526155141451 |
9 | 38388186201764 |
10 | 10010255213353 |
11 | 320a36411265a |
12 | 115807a272ba1 |
13 | 577c699922c5 |
14 | 2686db127653 |
15 | 1255ca414a6d |
hex | 91ab1b4c329 |
10010255213353 has 2 divisors, whose sum is σ = 10010255213354. Its totient is φ = 10010255213352.
The previous prime is 10010255213327. The next prime is 10010255213377. The reversal of 10010255213353 is 35331255201001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7147110334464 + 2863144878889 = 2673408^2 + 1692083^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10010255213353 is a prime.
It is a super-3 number, since 3×100102552133533 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (10010255213753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005127606676 + 5005127606677.
It is an arithmetic number, because the mean of its divisors is an integer number (5005127606677).
Almost surely, 210010255213353 is an apocalyptic number.
It is an amenable number.
10010255213353 is a deficient number, since it is larger than the sum of its proper divisors (1).
10010255213353 is an equidigital number, since it uses as much as digits as its factorization.
10010255213353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 31.
The spelling of 10010255213353 in words is "ten trillion, ten billion, two hundred fifty-five million, two hundred thirteen thousand, three hundred fifty-three".
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