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10010320033 = 77125577877
BaseRepresentation
bin10010101001010100…
…10101110010100001
3221211122011221112211
421110222111302201
5131000120220113
64333151522121
7503031213340
oct112452256241
927748157484
1010010320033
11427762366a
121b34529341
13c36b918bc
146ad68bb57
153d8c4ab3d
hex254a95ca1

10010320033 has 16 divisors (see below), whose sum is σ = 11607508224. Its totient is φ = 8455043520.

The previous prime is 10010320013. The next prime is 10010320043. The reversal of 10010320033 is 33002301001.

It is not a de Polignac number, because 10010320033 - 29 = 10010319521 is a prime.

It is a super-3 number, since 3×100103200333 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10010319995 and 10010320022.

It is not an unprimeable number, because it can be changed into a prime (10010320013) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1266891 + ... + 1274767.

It is an arithmetic number, because the mean of its divisors is an integer number (725469264).

Almost surely, 210010320033 is an apocalyptic number.

It is an amenable number.

10010320033 is a deficient number, since it is larger than the sum of its proper divisors (1597188191).

10010320033 is an equidigital number, since it uses as much as digits as its factorization.

10010320033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10512.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 10010320033 its reverse (33002301001), we get a palindrome (43012621034).

The spelling of 10010320033 in words is "ten billion, ten million, three hundred twenty thousand, thirty-three".

Divisors: 1 7 71 497 2557 7877 17899 55139 181547 559267 1270829 3914869 20141489 140990423 1430045719 10010320033