10010343404131 has 16 divisors (see below), whose sum is σ = 11706577341184. Its totient is φ = 8380660093344.

The previous prime is 10010343404099. The next prime is 10010343404153. The reversal of 10010343404131 is 13140434301001.

It is a happy number.

It is not a de Polignac number, because 10010343404131 - 2⁵ = 10010343404099 is a prime.

It is a super-2 number, since 2×10010343404131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10010343404096 and 10010343404105.

It is not an unprimeable number, because it can be changed into a prime (10010343404161) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48808060 + ... + 49012726.

It is an arithmetic number, because the mean of its divisors is an integer number (731661083824).

Almost surely, 2^{10010343404131} is an apocalyptic number.

10010343404131 is a deficient number, since it is larger than the sum of its proper divisors (1696233937053).

10010343404131 is a wasteful number, since it uses less digits than its factorization.

10010343404131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 367210.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 10010343404131 its reverse (13140434301001), we get a palindrome (23150777705132).

The spelling of 10010343404131 in words is "ten trillion, ten billion, three hundred forty-three million, four hundred four thousand, one hundred thirty-one".