Base | Representation |
---|---|
bin | 10110110000110010110000… |
… | …001101101011111101110001 |
3 | 111010110102112210112201221001 |
4 | 112300302300031223331301 |
5 | 101110200342323110022 |
6 | 552525531324202001 |
7 | 30041466315521035 |
oct | 2660626015537561 |
9 | 433412483481831 |
10 | 100110054113137 |
11 | 29997487757292 |
12 | b289bba699301 |
13 | 43b245090b453 |
14 | 1aa14d12801c5 |
15 | b8915b505b27 |
hex | 5b0cb036bf71 |
100110054113137 has 2 divisors, whose sum is σ = 100110054113138. Its totient is φ = 100110054113136.
The previous prime is 100110054113077. The next prime is 100110054113149. The reversal of 100110054113137 is 731311450011001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 83129918588721 + 16980135524416 = 9117561^2 + 4120696^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100110054113137 is a prime.
It is not a weakly prime, because it can be changed into another prime (100110054113737) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055027056568 + 50055027056569.
It is an arithmetic number, because the mean of its divisors is an integer number (50055027056569).
Almost surely, 2100110054113137 is an apocalyptic number.
It is an amenable number.
100110054113137 is a deficient number, since it is larger than the sum of its proper divisors (1).
100110054113137 is an equidigital number, since it uses as much as digits as its factorization.
100110054113137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1260, while the sum is 28.
The spelling of 100110054113137 in words is "one hundred trillion, one hundred ten billion, fifty-four million, one hundred thirteen thousand, one hundred thirty-seven".
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