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100110231333331 is a prime number
BaseRepresentation
bin10110110000110010111010…
…110001101110100111010011
3111010110110000011000110022221
4112300302322301232213103
5101110201223210131311
6552530001054441511
730041503600051012
oct2660627261564723
9433413004013287
10100110231333331
11299975687a045a
12b28a049b03297
1343b247b54ac7b
141aa150aa12a79
15b8916bd60671
hex5b0cbac6e9d3

100110231333331 has 2 divisors, whose sum is σ = 100110231333332. Its totient is φ = 100110231333330.

The previous prime is 100110231333323. The next prime is 100110231333337. The reversal of 100110231333331 is 133333132011001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100110231333331 - 23 = 100110231333323 is a prime.

It is a super-2 number, since 2×1001102313333312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100110231333296 and 100110231333305.

It is not a weakly prime, because it can be changed into another prime (100110231333337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055115666665 + 50055115666666.

It is an arithmetic number, because the mean of its divisors is an integer number (50055115666666).

Almost surely, 2100110231333331 is an apocalyptic number.

100110231333331 is a deficient number, since it is larger than the sum of its proper divisors (1).

100110231333331 is an equidigital number, since it uses as much as digits as its factorization.

100110231333331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 100110231333331 its reverse (133333132011001), we get a palindrome (233443363344332).

The spelling of 100110231333331 in words is "one hundred trillion, one hundred ten billion, two hundred thirty-one million, three hundred thirty-three thousand, three hundred thirty-one".