10011050505553 has 2 divisors, whose sum is σ = 10011050505554. Its totient is φ = 10011050505552.

The previous prime is 10011050505541. The next prime is 10011050505581. The reversal of 10011050505553 is 35550505011001.

10011050505553 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9594524835009 + 416525670544 = 3097503^2 + 645388^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10011050505553 is a prime.

It is a super-2 number, since 2×10011050505553² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10011050502553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005525252776 + 5005525252777.

It is an arithmetic number, because the mean of its divisors is an integer number (5005525252777).

Almost surely, 2^{10011050505553} is an apocalyptic number.

It is an amenable number.

10011050505553 is a deficient number, since it is larger than the sum of its proper divisors (1).

10011050505553 is an equidigital number, since it uses as much as digits as its factorization.

10011050505553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9375, while the sum is 31.

Adding to 10011050505553 its reverse (35550505011001), we get a palindrome (45561555516554).

The spelling of 10011050505553 in words is "ten trillion, eleven billion, fifty million, five hundred five thousand, five hundred fifty-three".