100111011110083 has 2 divisors, whose sum is σ = 100111011110084. Its totient is φ = 100111011110082.

The previous prime is 100111011110069. The next prime is 100111011110147. The reversal of 100111011110083 is 380011110111001.

It is a weak prime.

It is an emirp because it is prime and its reverse (380011110111001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100111011110083 - 2¹³ = 100111011101891 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 100111011110083.

It is not a weakly prime, because it can be changed into another prime (100111011110063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50055505555041 + 50055505555042.

It is an arithmetic number, because the mean of its divisors is an integer number (50055505555042).

Almost surely, 2^{100111011110083} is an apocalyptic number.

100111011110083 is a deficient number, since it is larger than the sum of its proper divisors (1).

100111011110083 is an equidigital number, since it uses as much as digits as its factorization.

100111011110083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 19.

Adding to 100111011110083 its reverse (380011110111001), we get a palindrome (480122121221084).

The spelling of 100111011110083 in words is "one hundred trillion, one hundred eleven billion, eleven million, one hundred ten thousand, eighty-three".